Mathematics

If $$\displaystyle \frac{3\mathrm{x}}{(\mathrm{x}-6)(\mathrm{x}+\mathrm{a})}$$ $$=\displaystyle \frac{2}{\mathrm{x}-6}+\frac{1}{\mathrm{x}+a}$$ then $$a=$$


ANSWER

3


SOLUTION
$$LHS=\dfrac{3x}{(x-6)(x+a)}   RHS=\dfrac{2}{x-6}+\dfrac{1}{x+a}$$
$$=\dfrac{2(x+a)+(x-6)}{(x-6)(x+a)}$$
$$LHS=RHS$$
$$\Rightarrow 3x=2(x+a)+(x-6)   -(1)$$
keep $$x=6$$ we get in eqn (1)
$$18=2(6+a)$$
$$a=3$$
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Single Correct Medium Published on 17th 09, 2020
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