Mathematics

If $$A,B,C$$ are the angles of a triangle, show that
$$\sin{B}\cos{(C+A)}+\cos{B}\sin{(C+A)}=0$$


SOLUTION
$$A+B+C=\pi $$ 
$$\therefore \sin B \cos(C+A) +\cos B\sin(C+A)$$ 
$$=\sin(A+B+C)$$ 
$$=\sin\pi =0$$
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Subjective Medium Published on 09th 09, 2020
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