Mathematics

If $A,B,C$ are the angles of a triangle, show that$\sin{B}\cos{(C+A)}+\cos{B}\sin{(C+A)}=0$

SOLUTION
$A+B+C=\pi$
$\therefore \sin B \cos(C+A) +\cos B\sin(C+A)$
$=\sin(A+B+C)$
$=\sin\pi =0$

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Subjective Medium Published on 09th 09, 2020
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