Mathematics

$$I = \int_{\frac{\pi }{4}}^{\frac{\pi }{3}} {\frac{{\sin x}}{x}dx} $$, then


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$$\frac{{\sqrt 3 }}{8} \le I \le \frac{{\sqrt 2 }}{6}$$


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Single Correct Medium Published on 17th 09, 2020
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