Mathematics

From the following figure, can we say that $$ AB> CD$$
If true then enter 1 else enter 0.


ANSWER

1


SOLUTION
$$
Given:\quad In\quad triangle\quad ABC\quad \\ \angle ABC\quad =\quad { 70 }^{ \circ  }\\ AB\quad =\quad AC\\ So\\ \angle ACB\quad =\quad { 70 }^{ \circ  }\\ In\quad \triangle \quad ACD\\ \angle ACD\quad =\quad 180^{ \circ  }\quad -\quad { 70 }^{ \circ  }\quad ={ 110 }^{ \circ  }\\ \angle ADC\quad =\quad 40^{ \circ  }\\ \angle CAD\quad =\quad 180^{ \circ  }\quad -\quad { 150 }^{ \circ  }\quad =\quad { 30 }^{ \circ  }\\ So\quad AC\quad >\quad CD\quad (\angle ADC\quad \quad >\quad \angle CAD\quad )\\ Since\quad AB\quad =\quad AC\quad (given)\\ AB\quad >\quad CD\\ \\ \\ 
$$
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