Mathematics

From the following figure, can we say that $AB> CD$If true then enter 1 else enter 0.

1

SOLUTION
$Given:\quad In\quad triangle\quad ABC\quad \\ \angle ABC\quad =\quad { 70 }^{ \circ }\\ AB\quad =\quad AC\\ So\\ \angle ACB\quad =\quad { 70 }^{ \circ }\\ In\quad \triangle \quad ACD\\ \angle ACD\quad =\quad 180^{ \circ }\quad -\quad { 70 }^{ \circ }\quad ={ 110 }^{ \circ }\\ \angle ADC\quad =\quad 40^{ \circ }\\ \angle CAD\quad =\quad 180^{ \circ }\quad -\quad { 150 }^{ \circ }\quad =\quad { 30 }^{ \circ }\\ So\quad AC\quad >\quad CD\quad (\angle ADC\quad \quad >\quad \angle CAD\quad )\\ Since\quad AB\quad =\quad AC\quad (given)\\ AB\quad >\quad CD\\ \\ \\$

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