Mathematics

Find the measure of an angle which is ${ 30 }^{ \circ }$ less than its supplement.

SOLUTION
Consider the required angle as ${x}^{o}$

We know that the complement can be written as ${180}^{o}-{x}^{o}$

To find the measure of an angle is equal to its complement

We get

${x}^{o}=[{180}^{o}-{x}^{o}]+{30}^{o}$

We can also write it as

$x+x=90+36$

So we get

$2x=150$

By division we get

$x=\dfrac{150}{2}$

${x}^{o}={75}^{o}$

Therefore the measure of an angle which is ${30}^{o}$ more than its complement is ${75}^{o}$

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Subjective Medium Published on 09th 09, 2020
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Subjects 10
Chapters 88
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