Mathematics

Find the following integrals
$$(4e^{3x}+1)dx$$


SOLUTION
$$\displaystyle\int (4e^{3x}+1)dx=\dfrac{4e^{3x}}{3}+x=\dfrac{4}{3}e^{3x}+x+C$$
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Subjective Medium Published on 17th 09, 2020
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