Mathematics

Find the distance of $$(1,-3)$$ from the line $$2y-3x=4$$.


SOLUTION
The distance of the point $$P (1, – 3)$$ from the line $$2y – 3 x – 4 = 0$$ is the length of perpendicular from the point to the line which is given by 
$$\left| {\frac{{2\left( { - 3} \right) - 3 - 4}}{{\sqrt {13} }}} \right| = \sqrt {13} \,units$$
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