Mathematics

Find the complement of $${58}^{\circ}{20}^{\prime}{25}^{\prime\prime}$$


SOLUTION
We write $${90}^{\circ}={89}^{\circ}{59}^{\prime}{60}^{\prime\prime}$$

Complement of $${58}^{\circ}{20}^{\prime}{25}^{\prime\prime}$$

$$={90}^{\circ}-{58}^{\circ}{20}^{\prime}{25}^{\prime\prime}$$

$$={89}^{\circ}{59}^{\prime}{60}^{\prime\prime}-{58}^{\circ}{20}^{\prime}{25}^{\prime\prime}$$

$$={31}^{\circ}{39}^{\prime}{35}^{\prime\prime}$$
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