Mathematics

Find the angles when
(i)The angles are complementary and the smaller is $$40^ \circ$$ less than the larger. 
(ii)The angles are complementary and the larger is four times the smaller. 


SOLUTION
As we know when angles are complementary if their sum is $$90^\circ$$ then
$$i)$$If one angle is $$x$$ then other is $$x+40^\circ$$
                  $$x+x+40^\circ=90^\circ$$
    $$x=25^\circ$$ and larger angle is $$65^\circ.$$

$$ii)$$If one angle is $$x$$ then other is $$4x$$
                  $$x+4x=90^\circ$$
    $$x=18^\circ$$ and larger angle is $$72^\circ.$$
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