Mathematics

Find the angle which is five times its supplement.


SOLUTION
Consider the required angle as $${x}^{o}$$

We know that the complement can be written as $${180}^{o}-{x}^{o}$$

To find the measure of an angle is equal to its complement 

We get

$${x}^{o}=5[{180}^{o}-{x}^{o}]$$

We can also write it as

$$x=900-5x$$

so we get

$$6x=900$$

By division we get

$$x=\dfrac{900}{2}$$

$${x}^{o}={150}^{o}$$

Therefore the measure of an angle which is five times than its supplement is $${150}^{o}$$
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