Mathematics

# Find smallest of two supplementary angles, if they are in the ratio $7 : 11$.

$70$

##### SOLUTION
Two angles whose sum is ${ 180 }^{ o }$ are said to be supplementary.
Given two angles are the ratio of $7:11$
Let the two angles be $7x$ and $11x$.
So, $7x+11x={ 180 }^{ o }$
$\Rightarrow 18x={ 180 }^{ o }$
$\Rightarrow x=\dfrac { 180 }{ 18 }$
$\Rightarrow x={ 10 }$
Therefore, the two angles are $7x={ 70 }^{ o }$ and $11x={ 110 }^{ o }$.

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Single Correct Medium Published on 09th 09, 2020
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