Mathematics

Evaluate:$\displaystyle\int_{0}^{\frac{\pi}{2}}{\dfrac{\sqrt{\cot{x}}dx}{\sqrt{\cot{x}}+\sqrt{\tan{x}}}}$

SOLUTION

Its FREE, you're just one step away

Subjective Medium Published on 17th 09, 2020
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 84

Realted Questions

Q1 Subjective Medium
Evaluate $\displaystyle\int^4_1\sqrt{x}dx$.

1 Verified Answer | Published on 17th 09, 2020

Q2 Single Correct Medium
$\displaystyle \int \sqrt{x^2 + 2x + 5} \ dx$ is equal to
• A. $(x + 1) \sqrt{x^2 + 2x + 5} + \dfrac{1}{2} log |x + 1 + \sqrt{x^2 + 2x + 5}| + C$
• B. $(x + 1) \sqrt{x^2 + 2x + 5} + 2 log |x + 1 + \sqrt{x^2 + 2x + 5}| + C$
• C. $(x + 1) \sqrt{x^2 + 2x + 5 - 2} log |x + 1 + \sqrt{x^2 + 2x + 5}| + C$
• D. $\dfrac{1}{2}(x + 1) \sqrt{x^2 + 2x + 5} + 2 log |x + 1 + \sqrt{x^2 + 2x + 5}| + C$

1 Verified Answer | Published on 17th 09, 2020

Q3 Single Correct Hard
Consider $I=\displaystyle \int^{\pi}_{0}\displaystyle\frac{xdx}{1+\sin x}$. What is I equal to?
• A. $-\pi$
• B. $0$
• C. $2\pi$
• D. $\pi$

1 Verified Answer | Published on 17th 09, 2020

Q4 Single Correct Medium
$\displaystyle\int^{1}_{-1}x^3(1-x^2)dx=?$
• A. $-\dfrac{40}{3}$
• B. $\dfrac{40}{3}$
• C. $\dfrac{5}{6}$
• D. $0$

1 Verified Answer | Published on 17th 09, 2020

Q5 One Word Medium
$I = \int_0^1 x.e^{-x^2} dx=m\dfrac{e-1}{4e}$. Find $m$