Mathematics

# Evaluate: $\displaystyle\int e^{e^x} . e^x . dx$

##### SOLUTION
$\displaystyle\int e^{e^x} . e^x . dx$
$=\displaystyle\int d\left(e^{e^x} \right)$
$=e^{e^x}+c$ [$c$ being integrating costant]

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Subjective Medium Published on 17th 09, 2020
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 86

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