Mathematics

Evaluate:  $$\int {\frac {e^{2x}}{1+e^x}}dx$$


SOLUTION
$$l = (1-e^{x})-log|e^{x}+1|+c $$
$$ = (t-logt)+c $$
$$ = (e^{x}+1)-log(e^{x}+1)+c $$
$$ = e^{x}-log(e^{x}+1)+1+c $$
$$ = e^{x}-log(e^{x}+1)+c $$ 
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Subjective Medium Published on 17th 09, 2020
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