Mathematics

Evaluate the following definite integral:

$$\displaystyle \int_{0}^{4} {4x-x^2}dx$$


SOLUTION
Consider, $$I=\displaystyle \int_{0}^{4} {4x-x^2}dx$$

$$I=\left [ 2x^2-\dfrac{x^3}3 \right]_0^4$$ 

$$I=32-\dfrac{64}3 $$ 

$$I=\dfrac {32}3$$

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Subjective Medium Published on 17th 09, 2020
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