Mathematics

# Evaluate :$\int \dfrac{1}{\sin^2x \cos^2x}dx$

##### ANSWER

$-2\cot 2x +C$

##### SOLUTION
$I=\int \dfrac{1}{\sin^2x \cos^2x}dx$

$I=\int \dfrac{4}{(2\sin x \cos x)^2}dx$

$I=4 \int \dfrac{1}{\sin^22x}dx$

$I=4\int \csc^2 2x \ dx=-\dfrac{4}{2} \cot 2x +C=-2\cot 2x +C$

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Single Correct Medium Published on 17th 09, 2020
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 84

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