Mathematics

Evaluate $$\displaystyle\int^{3}_{2}3^{x}dx$$


ANSWER

$$\dfrac{18}{\ln 3}$$


SOLUTION
$$I=\displaystyle\int_{2}^{3}3^{x}dx$$ $$=$$ $$\left [ \dfrac{3^{x}}{\ln{3}} \right ]_{2}^{3}$$ 

$$=\dfrac{3^{3}}{\ln3}-\dfrac{3^{2}}{\ln3}=\dfrac{27-9}{\ln3}=\dfrac{18}{\ln3}$$.
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Single Correct Medium Published on 17th 09, 2020
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