Mathematics

Evaluate: $$\displaystyle\int \dfrac {1}{2x+3}dx$$


SOLUTION

Let $$t=2x+3 \implies dt=2 dx$$

$$\Rightarrow \displaystyle \int \dfrac 1{2t }dt $$

$$\Rightarrow \dfrac12 \log t$$ 

$$\Rightarrow \dfrac12[\log 2x+3]$$ 
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Subjective Medium Published on 17th 09, 2020
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