Mathematics

Evaluate: $$\displaystyle \int{\dfrac{(2x+3)dx}{x^2+3x+6}}$$


SOLUTION
$$\displaystyle \int{\dfrac{(2x+3)dx}{x^2+3x+6}}\\t=x^2+3x+6\implies dt=2x+3dx\\\displaystyle \int \dfrac{dt}{t}\\\log t+c\\\log(x^2+3x+6)+c$$
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Subjective Medium Published on 17th 09, 2020
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