Mathematics


Evaluate: $$\displaystyle \int  (x^3+5x^2+6)(3x^2+5x)d x $$


SOLUTION

 $$\displaystyle \int  (x^3+5x^2+6)(3x^2+5x)d x \\t=x^3+5x^2+6\implies 3x^2+5x dx =dt \\\displaystyle\int tdt\\\dfrac{t^2}{2}+c\\\dfrac{x^3+5x^2+6}{2}+c $$
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Subjective Medium Published on 17th 09, 2020
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