Mathematics

Evaluate: $$\displaystyle \int _0^1 (8x^2+16) dx$$


SOLUTION
$$I=\displaystyle \int _0^1 (8x^2+16)dx$$

$$I=8\displaystyle \int (x^2+2)dx$$

$$I=8 \left.\dfrac{x^3}3+16x\right|_0^1$$

$$I=\dfrac 83+16=\dfrac {56}3$$
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Subjective Medium Published on 17th 09, 2020
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