Mathematics

$$\displaystyle\int_{}^{} {x{{\sec }^2}xdx} $$


SOLUTION
Now,
$$\displaystyle\int_{}^{} {x{{\sec }^2}xdx} $$
$$=x.\displaystyle\int_{}^{} {{{\sec }^2}xdx} $$$$-\displaystyle\int 1. \left(\displaystyle\int_{}^{} {{{\sec }^2}xdx}\right) dx $$ [ Using method of by parts]
$$=x\tan x-\log|\sec x|+c$$ [ Where $$c$$ is integrating constant]
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Subjective Medium Published on 17th 09, 2020
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