Mathematics

$$\displaystyle \int\frac{dt}{(6t-1)}$$ is equal to:


ANSWER

$$\dfrac{1}{6} \ln(6t-1) +C$$


SOLUTION
Formula : $$\displaystyle \int \dfrac {dt} {at+b} =\dfrac {1}{a}\ln(at+b)+C$$

$$\Rightarrow \displaystyle \int \dfrac {dt} {6t-1}=\dfrac {1}{6}\ln(6t-1)+C$$
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