Mathematics

# $\displaystyle \int\frac{dt}{(6t-1)}$ is equal to:

$\dfrac{1}{6} \ln(6t-1) +C$

##### SOLUTION
Formula : $\displaystyle \int \dfrac {dt} {at+b} =\dfrac {1}{a}\ln(at+b)+C$

$\Rightarrow \displaystyle \int \dfrac {dt} {6t-1}=\dfrac {1}{6}\ln(6t-1)+C$

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Single Correct Medium Published on 17th 09, 2020
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 111

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