Mathematics

# $\displaystyle \int (x^2-x+5)\, dx$

$\dfrac {x^3}3-\dfrac{x^2}2+5x+c$

##### SOLUTION
Given

$\displaystyle \int x^2-x+5 \, dx$

$\implies \displaystyle \int x^2 dx-\int x dx+\int 5 dx$

$\implies \dfrac{x^3}3-\dfrac{x^2}2+5x+c$

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Single Correct Medium Published on 17th 09, 2020
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 84

#### Realted Questions

Q1 Single Correct Medium
If $\dfrac{dy}{dx}=\dfrac{1}{x}+3x^2$ then $y=$
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• B. $\ln {x} +3x^3+c$
• C. $\ln{x} +\dfrac{x^3}{3}+c$
• D. $\ln{x} +x^3+c$

1 Verified Answer | Published on 17th 09, 2020

Q2 Subjective Medium
Find the value of $\displaystyle\int\limits_{0}^{\dfrac{\pi}{2}}\log(\tan x)dx$.

1 Verified Answer | Published on 17th 09, 2020

Q3 Single Correct Medium
$\int_{0}^{1}\dfrac{x}{(1-x)^{5/4}} dx =$
• A. $16/3$
• B. $3/16$
• C. $-3/16$
• D. $-16/3$

1 Verified Answer | Published on 17th 09, 2020

Q4 One Word Medium
$\displaystyle \int \frac{\sqrt{\tan x}dx}{\sin x\cos x}=k\sqrt{\tan x}.$ Find the value of $k$.

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