Mathematics

$$\displaystyle \int (x^2-x+5)\, dx$$


ANSWER

$$\dfrac {x^3}3-\dfrac{x^2}2+5x+c$$


SOLUTION
Given 

$$\displaystyle \int x^2-x+5 \, dx$$

$$\implies \displaystyle \int x^2 dx-\int x dx+\int 5 dx$$

$$\implies \dfrac{x^3}3-\dfrac{x^2}2+5x+c$$
View Full Answer

Its FREE, you're just one step away


Single Correct Medium Published on 17th 09, 2020
Next Question
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 84
Enroll Now For FREE

Realted Questions

Q1 Single Correct Medium
If $$\dfrac{dy}{dx}=\dfrac{1}{x}+3x^2$$ then $$y=$$
  • A. $$\ln {x} +\dfrac{x^3}2 + c$$
  • B. $$\ln {x} +3x^3+c$$
  • C. $$\ln{x} +\dfrac{x^3}{3}+c$$
  • D. $$\ln{x} +x^3+c$$

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer
Q2 Subjective Medium
Find the value of $$\displaystyle\int\limits_{0}^{\dfrac{\pi}{2}}\log(\tan x)dx$$.

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer
Q3 Single Correct Medium
$$\int_{0}^{1}\dfrac{x}{(1-x)^{5/4}} dx =$$
  • A. $$16/3$$
  • B. $$3/16$$
  • C. $$-3/16$$
  • D. $$-16/3$$

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer
Q4 One Word Medium
$$\displaystyle \int \frac{\sqrt{\tan x}dx}{\sin x\cos x}=k\sqrt{\tan x}.$$ Find the value of $$k$$.

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer
Q5 Subjective Easy
Evaluate $$\int \dfrac{e^x-e^{-x}}{e^x+e^{-x}}dx$$

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer