Mathematics

$$\displaystyle \int _{}{ \sin ^{ 8 }{ x } \cos ^{ }{ x } dx } $$


SOLUTION
Let $$\sin x=t\implies \cos dx=dt$$
$$\displaystyle \int t^8dt\\\dfrac{t^9}{9}+c\\\dfrac{\sin ^9t}{9}+c$$
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Subjective Medium Published on 17th 09, 2020
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