Mathematics

$\displaystyle \int \dfrac { 1 } { x \left\{ 6 ( \log x ) ^ { 2 } + 7 \log x + 2 \right\} } d x =$

$\log \left| \dfrac { 2 \log x + 1 } { 3 \log x + 2 } \right|$

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Single Correct Medium Published on 17th 09, 2020
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 84

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