Physics

# Dimensions of ohm are same as:

$\dfrac { h }{ e^{2} }$

##### SOLUTION
$ohm=ML^{2}I^{-2}T^{-3}$
$h=M^{1}L^{2}T^{-1}$
$e=IT$

$\dfrac{h}{e}=\dfrac{M^{1}L^{2}T^{-1}}{IT}=M^{1}L^{2}I^{-1}T^{-2}$

$\dfrac{h^{2}}{e}=M^{2}L^{4}T^{-1}I^{-1}$

$\dfrac{h}{e^{2}}=M^{1}L^{2}T^{-3}I^{-2}$

$\dfrac{h^{2}}{e^{2}}=M^{2}L^{4}T^{-4}I^{2}$

You're just one step away

Single Correct Medium Published on 18th 08, 2020
Questions 244531
Subjects 8
Chapters 125
Enrolled Students 218

#### Realted Questions

Q1 Single Correct Medium
Count total number of S.F. in $1.60\, \times\, 10^{- 19}$
• A. 3
• B. 5
• C. 2`
• D. 22

Asked in: Physics - Units and Measurement

1 Verified Answer | Published on 18th 08, 2020

Q2 Single Correct Medium
The density of a cube is measured by measuring its mass ad length of its side. If the maximum errors in the measurement of its mass and length are $3\%$ and $2\%$ respectively, the maximum error in the measurement of density would be:
• A. $12\%$
• B. $14\%$
• C. $7\%$
• D. $9\%$

Asked in: Physics - Units and Measurement

1 Verified Answer | Published on 18th 08, 2020

Q3 Single Correct Medium
The Van der Waal's equation of state for some gases can be expressed as:
$(P + \dfrac{a}{V^2})(V - b) = RT$
where P is the pressure, V is the molar volume, and T is the absolute temperature of the given sample of gas and a,b and R are constants.
In the above problem, the dimensional formula for RT is same as that of
• A. Energy
• B. Force
• C. Specific heat
• D. Latent heat

Asked in: Physics - Units and Measurement

1 Verified Answer | Published on 18th 08, 2020

Q4 Single Correct Medium
$M^{-1}L^{-2}T^3\theta^1$ are the dimensions of :
• A. coefficient of thermal conductivity
• B. coefficient of viscosity
• C. modulus of rigidity
• D. thermal resistance

Asked in: Physics - Units and Measurement

1 Verified Answer | Published on 18th 08, 2020

Q5 Single Correct Medium
If the velocity of light $c$, gravitational constant $G$ and Planck's constant $h$ be taken as fundamental units the dimension of mass in the new system will be
• A. $\;c^{1/2}h^{1/2}G^{1/2}$
• B. $\;c^{1/2}h^{1/2}G^{-1/2}$
• C. $\;c^{-3/2}h^{1/2}G^{1/2}$
• D. $\;c^{-5/2}h^{1/2}G^{1/2}$

Asked in: Physics - Units and Measurement

1 Verified Answer | Published on 18th 08, 2020