Mathematics

Differentiate the following function with respect to x.
$$(2x^2-3)\sin x$$.


SOLUTION

Given expression 

$$(2x^2-3)\sin x$$

$$\dfrac d{dx} ((2x^2-3)\sin x)$$

$$\dfrac d{dx}(2x^2-3)\sin x+2x^2-3\dfrac d{dx}(\sin x)$$

$$\implies 4x\sin x+(2x^2-3)\cos x$$

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Subjective Medium Published on 17th 09, 2020
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