Mathematics

# $\angle PQR$ and $\angle QOR$ form a linear pair. If $a-b=80$, find the values of a and b

$a=130^o$

$b=50^o$

##### SOLUTION
$As\quad \angle POR\quad and\quad \angle QOR\quad form\quad a\quad linear\quad pair\quad (given)\\ \angle POR+\angle QOR=180\quad (Linearpairaxiom)\\ or\quad a\quad +\quad b=180...........(1)\\ Also\quad a\quad -\quad b\quad =\quad 80...........(2)[Given]\\ Adding\quad equations(1)\quad and\quad (2),we\quad get\quad 2\quad a\quad =260\\ \quad a\quad =\quad \frac { 260 }{ 2 } =130\\ Substituting\quad the\quad value\quad of\quad a\quad in\quad (1),\\ we\quad get\quad 130+b=180\\ \quad b\quad =180-130=50\\ Hence\quad a\quad =130\quad b\quad =50$

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Multiple Correct Medium Published on 09th 09, 2020
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