Mathematics

$AB\parallel CD$ and $ACM$ is a straight line $\angle BAC$ is equal to:

Answer & Solution

${108}^{o}$

SOLUTION
As $AB \parallel CD$ and $ACM$ is a straight line cutting them,  it is called the transversal.

When a transversal cuts two parallel lines, the corresponding angles are equal.
This means $\angle BAC = 3{x}^{o}$

Since $LAC$ is a straight line, we have, $\angle LAB + \angle BAC = {180}^{o}$
$=> 2{x}^{o} + 3{x}^{o} ={180}^{o}$
$=> 5{x}^{o} = {180}^{o}$
$=> {x}^{o} = {36}^{o}$

$=> \angle BAC = 3{x}^{o} = 3\times {36}^{o} = {108}^{o}$

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Single Correct Medium Published on 09th 09, 2020
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